How to write a code for video streaming in php

 Here's a simple example of how to stream a video file in PHP:

<?php // Specify the video file path 
$file = 'path/to/video.mp4'
// Check if the file exists 
if (file_exists($file)) { 
// Set the appropriate headers for video streaming 
header('Content-Type: video/mp4'); 
header('Content-Length: ' . filesize($file)); 
// Stream the video content 
readfile($file); exit; } else
// Handle the case if the file does not exist 
header("HTTP/1.0 404 Not Found"); 
echo 'File not found'; exit
} ?>

This code will read the specified video file and send its contents to the client using the appropriate Content-Type and Content-Length headers. The video content is streamed using the readfile function. If the file does not exist, it will return a 404 Not Found error.


Most Popular

PhpStorm, return value is expected to be 'A', 'object' returned

Remove Unicode Zero Width Space PHP

Laravel file upload returns forbidden 403, file permission is 700 not 755